Match List-I with List-II:List-IList-IIA. Coe | vedclass

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(C) $1$. Coefficient of Viscosity $(\eta)$: From $F = \eta A \frac{dv}{dy}$,we have $\eta = \frac{F}{A(dv/dy)}$. Dimensions: $\frac{[M L T^{-2}]}{[L^2

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$A-III, B-IV, C-II, D-I$

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(C) $1$. Coefficient of Viscosity $(\eta)$: From $F = \eta A \frac{dv}{dy}$,we have $\eta = \frac{F}{A(dv/dy)}$. Dimensions: $\frac{[M L T^{-2}]}{[L^2][T^{-1}]} = [M L^{-1} T^{-1}]$. (Matches $III$)$2$. Surface Tension $(S)$: $S = \frac{F}{l}$. Dimensions: $\frac{[M L T^{-2}]}{[L]} = [M L^0 T^{-2}]$. (Matches $IV$)$3$. Angular momentum $(L)$: $L = mvr$. Dimensions: $[M][L T^{-1}][L] = [M L^2 T^{-1}]$. (Matches $II$)$4$. Rotational Kinetic energy $(K)$: $K = \frac{1}{2} I \omega^2$. Dimensions: $[M L^2][T^{-1}]^2 = [M L^2 T^{-2}]$. (Matches $I$)Thus,the correct matching is $A-III, B-IV, C-II, D-I$.

List-$I$	List-$II$
$A$. Coefficient of Viscosity	$I$. $[M L^2 T^{-2}]$
$B$. Surface Tension	$II$. $[M L^2 T^{-1}]$
$C$. Angular momentum	$III$. $[M L^{-1} T^{-1}]$
$D$. Rotational Kinetic energy	$IV$. $[M L^0 T^{-2}]$

Column-$I$	Column-$II$
$(a)$ Ratio of change in time period of a simple pendulum with temperature to its original time period	$(i) \, \alpha \Delta T$
$(b)$ Ratio of the value of a length to its scale reading	$(ii) \, T$
$(c)$ Reciprocal of coefficient of volume expansion for an ideal gas of constant pressure	$(iii) \, (1 + \alpha \Delta T)$
$(d) \, \frac{F}{YA} =$	$(iv) \, \frac{1}{2} \alpha \Delta T$

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A$. Coefficient of Viscosity $I$. $[M L^2 T^{-2}]$
$B$. Surface Tension $II$. $[M L^2 T^{-1}]$
$C$. Angular momentum $III$. $[M L^{-1} T^{-1}]$
$D$. Rotational Kinetic energy $IV$. $[M L^0 T^{-2}]$

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Match List-$I$ with List-$II$:List-$I$List-$II$$A$. Coefficient of Viscosity$I$. $[M L^2 T^{-2}]$$B$. Surface Tension$II$. $[M L^2 T^{-1}]$$C$. Angular momentum$III$. $[M L^{-1} T^{-1}]$$D$. Rotational Kinetic energy$IV$. $[M L^0 T^{-2}]$